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10k^2-45k=-50
We move all terms to the left:
10k^2-45k-(-50)=0
We add all the numbers together, and all the variables
10k^2-45k+50=0
a = 10; b = -45; c = +50;
Δ = b2-4ac
Δ = -452-4·10·50
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-5}{2*10}=\frac{40}{20} =2 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+5}{2*10}=\frac{50}{20} =2+1/2 $
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